如何使用JAXB将XML结构映射到Java对象?

如何使用jaxb构建java对象映射以下xml结构

给定以下xml结构:


    我是
        张三
    
    他是
        李四
    

想要使用jaxb构建java对象来映射该xml结构,可以按照以下步骤进行:

第一步:定义java类来映射xml元素
@data
@xmlaccessortype(xmlaccesstype.field)
@xmlrootelement(name = "speak")
public class speakxbj {

    private string version = "1.0";
    private string xmlns = "http://www.w3.org/2001/10/synthesis";
    private string mstts = "http://www.w3.org/2001/mstts";
    private string emo = "http://www.w3.org/2009/10/emotionml";
    private string lang = "zh-cn";

    private list voice;
}

@data
@xmlaccessortype(xmlaccesstype.field)
public class voicexbj {

    private string name;

    // 使用 @xmlmixed 注解处理混合内容
    @xmlmixed
    @xmlelementref(type = breakxbj.class)
    private list content;
}

@data
@xmlaccessortype(xmlaccesstype.field)
@xmlrootelement(name = "break")
public class breakxbj {

    private string time;
}

第二步:将xml转换为java对象

@slf4j
public class ssmltest {

    @test
    public void test1() {
        speakxbj xbj = new speakxbj();
        list voicelist = new arraylist<>();
        voicexbj voice = new voicexbj();
        voice.setname("zh-cn-yunxineural");

        // 将文本和换

行标签组合到 list 中 list breaklist = new arraylist<>(); breaklist.add("我是"); breakxbj breakxbj = new breakxbj(); breakxbj.settime("1000ms"); breaklist.add(breakxbj); breaklist.add("张三"); voice.setcontent(breaklist); voicelist.add(voice); voicexbj voice1 = new voicexbj(); voice1.setname("zh-cn-xiaoxiaoneural"); list breaklist1 = new arraylist<>(); breaklist1.add("他是"); breakxbj breakxbj1 = new breakxbj(); breakxbj1.settime("100ms"); breaklist1.add(breakxbj1); breaklist1.add("李四"); voice1.setcontent(breaklist1); voicelist.add(voice1); xbj.setvoice(voicelist); system.out.println(xmlutil.converttoxml(xbj)); } }

输出结果



    我是
        张三
    他是
        李四